Q. Write a method to replace all spaces in a string with '%20'. You may assume that the string has sufficient space at the end of the string to hold the additional characters, and that you are given the "true" length of the string.
EXAMPLE
Input: "Mr John Smith ", 13
Output: "Mr%20John%20Smith"
Source:
Output:
A%20string!%20WOW!%20
%20another%20string!%20
one%20%20more!
%20
EXAMPLE
Input: "Mr John Smith ", 13
Output: "Mr%20John%20Smith"
Source:
public class Code { //Required Function public static String replace(char[] s, int length){ int spaces = (s.length - length)/2; int offset = spaces * 2; int i=length-1; int j=i+offset; while(i>=0){ for(;i>=0 && s[i]!=' ';i--, j--) s[j] = s[i]; if(j>=2){ s[j--] = '0';s[j--] = '2';s[j--] = '%'; } i--; } return new String(s); } public static void problemTester(String s){ char a[] = s.toCharArray(); int blanks = 0; for(char c:a)if(c==' ')blanks++; char b[] = new char[a.length+2*blanks]; for(int i=0;i<a.length;++i)b[i]=a[i]; System.out.println(replace(b, a.length)); } public static void main(String[] args){ String s = "A string! WOW! "; problemTester(s); s = " another string! "; problemTester(s); s = "one more!"; problemTester(s); s = " "; problemTester(s); } }
Output:
A%20string!%20WOW!%20
%20another%20string!%20
one%20%20more!
%20
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