Bit Manipulation in Java

The >> Operator (Shifts bits right. Inserts duplicate bits of the bit initially at the Most Significant Position)

#1

10000000 00000000 00000000 00001000 >> 3 

=

11110000 00000000 00000000 00000001

#2

00000000 00000000 00000000 00001000 >> 3

=

00000000 00000000 00000000 00000001

The >>> Operator (Shifts bits right. Inserts 0s at the left)

#1

10000000 00000000 00000000 00001000 >>> 3

=

00010000 00000000 00000000 00000001

#2

00000000 00000000 00000000 00001000 >>> 3

=

00000000 00000000 00000000 00000001

There is no <<< Operator (that'd be useless)

The << Operator (Shifts bits left, inserts 0s at the right)

#1

10000000 00000000 00000000 00001000 << 3

=

00000000 00000000 00000000 10000000

#2

10000000 00000000 00000000 00010001 << 3

=

00000000 00000000 00000000 01001000

For working with these 32 bit binary string representations, use

int A = (int)Long.parseLong("10000000000000000000000000001001", 2);

#Note

int A = (int)Long.parseLong("10000000000000000000000000001001", 2); 
        System.out.println(Integer.toBinaryString(A));
int A = Integer.parseInt(   "-0000000000000000000000000001001", 2);
        System.out.println(Integer.toBinaryString(A));

Output:

10000000000000000000000000001001
11111111111111111111111111110111

These are different because the '-' sign does not just set the 32nd bit to 1. It takes the two's complement of the number represented by the rest of the string and then puts a 1 bit at the 32nd position.

Two's complement is calculated by inverting bits and adding 1. (One's complement + Add 1)

                 11000 
inverted bits =  00111
                +    1 
                 01000

So in the second case,

          0000000000000000000000000001001 (31 bits)
invert =  1111111111111111111111111110110 
                                       +1
          1111111111111111111111111110111  

So the output is 
         11111111111111111111111111110111 (32 bits)